Math, asked by AlekhyaSistu, 1 year ago

Formula of sum to n terms for a Geometric Progression.

Answers

Answered by Anonymous
6
Sn= [a1(1-r^n)] /(1-r)
*r ≠ 0
Answered by TPS
8
Sum of first n terms of a geometric progression with
first term=a
common ratio = r

is given by

\boxed{S_n= \frac{a(1-r^n)}{1-r} }
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