Formula to find distance between two points in 3d
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By using the the Pythagorean theorem twice, you can show that d((0,0,0),(1,2,3)) √(√1²+2²)²+3² = √1²+2²+3²
In general, if you have two points (x1,…,xn)(x1,…,xn) and (y1,…,yn)(y1,…,yn) in RnRn, you can use the Pythagorean theorem n−1n−1 times to show that the distance between them is
√∑(till n and i=1) (xi-yi)²
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