formula to find sum of all angles of any polygon
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(n-2)*180 is the correct formula
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suppose we have a quadrilateral of four sides
let side 1,2,3 and 4 be x.
Sum of all angles of a quadrilateral is 360°
add all four sides
4x = 360°
divide we get,
x= 360÷4
x= 90°
then 90° each angle
Hence prove
let side 1,2,3 and 4 be x.
Sum of all angles of a quadrilateral is 360°
add all four sides
4x = 360°
divide we get,
x= 360÷4
x= 90°
then 90° each angle
Hence prove
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