formula to find the angle between the hour and minute hand in a clock at any time?
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We know that if a object complete a revolution then it makes angle of 360°.
In a analog watch there is 12 hours.
It means that a analog watch is divided in 12 sections.
Now, each section is divided into 5 section.
∴ A analog watch is divided into ( 12 × 5 = 60 ) sub-sections.
The value of each sub - section is 1 min.
Hence, if any needle complete 1 min then it makes the angle of 360°/60 = 60°.
So, to find the angle between the hour and minute needles we have to first find their distance into sub - sections ( that's minute section ).
Angle between hour and minute needle = 6° × Distance between them according to sub-section.
In a analog watch there is 12 hours.
It means that a analog watch is divided in 12 sections.
Now, each section is divided into 5 section.
∴ A analog watch is divided into ( 12 × 5 = 60 ) sub-sections.
The value of each sub - section is 1 min.
Hence, if any needle complete 1 min then it makes the angle of 360°/60 = 60°.
So, to find the angle between the hour and minute needles we have to first find their distance into sub - sections ( that's minute section ).
Angle between hour and minute needle = 6° × Distance between them according to sub-section.
Anonymous:
Is it satisfactory ?
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