Question

formula trigonometry

Answer 1

hello there
let ,
p=perpendicular , b=base, h=hypotenuse and let A be an angle of a right triangle

sinA=P/h

cosa=b/h

tanA=p/h

cosecA=h/p=1/sinA

secA=h/b=1/cosA

cotA=b/p=1/tanA

tan A=SinA/cosA
CotA=cosA/sinA

sin²A +cos²A=1
cosec²A=1+cot²A
cosec A+cotA=1/cosecA-cotA
cosecA-cotA=1/cosecA+cotA
sec²A=1+tan²A
secA-tanA=1/secA+tanA
secA+tanA=1/secA-tanA

Answer 2

ʜᴇʟʟᴏ

ꜱᴏᴍᴇ ᴛʀɪɢᴏɴᴏᴍᴇᴛʀɪᴄ ꜰᴏʀᴍᴜʟᴀꜱ ᴀʀᴇ ɢɪᴠᴇɴ ɪɴ ᴀᴛᴀᴄʜᴍᴇɴᴛ