Question

Formula used: E°cell=E°cell - (0.059x log Qc]/n
Write the Nernst equation and calculate E°cell of the following cell at 298 K. Mg/Mg+2 (0.001 M) Cu+2 (0.0001M) / Cu
[E° Mg 2+/Mg = -2.36 V, E°cu2+/cu = 0.34v]
a. Write the anode reaction.
b. Write the cathode reaction
c. Write the E oxid.pot of corresponding anode
d. Write E oxid. pet of corresponding cathode.
e. add both half cell reaction to give complete cell reaction.
f. Find E°cell adding both cell pot.
g. Now write the Nernst equation & calculate E cell
E cell = E°cell - [(0.059x log Qc)/n]​

Answer 1

Answer:

Write the Nernst equation and calculate E°cell of the following cell at 298 K. Mg/Mg+2 (0.001 M) Cu+2 (0.0001M) / Cu

[E° Mg 2+/Mg = -2.36 V, E°cu2+/cu = 0.34v]

a. Write the anode reaction.

b. Write the cathode reaction

c. Write the E oxid.pot of corresponding anode

d. Write E oxid. pet of corresponding cathode.

e. add both half cell reaction to give complete cell reaction.

f. Find E°cell adding both cell pot.

g. Now write the Nernst equation & calculate E cell

E cell = E°cell - [(0.059x lol ha ha ha