Physics, asked by deshpandepranav454, 11 months ago

Formulae for projectile motion

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Answered by blossomag
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Few Examples of Two – Dimensional Projectiles

Quantity Value

Equation of path of projectile motion y = (tan θ0)x – gx2/2(v0cosθ0)2

Time of maximum height tm = v0 sinθ0 /g

Time of flight 2tm = 2(v0 sinθ0/g)

Maximum height of projectile hm = (v0 sinθ0)2/2g

Answered by ektasahu2007
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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. ... The maximum height of an object, given the initial launch angle and initial velocity is found with:h=v2isin2θi2g h = v i 2 sin 2 ⁡ θ i 2 g .

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