Formulate the following problems as a pair of equations,hence find their solutions.
1. Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water and the speed of the current.(Based on NCERT Text book)
Answers
Answered by
4
Speed downstream = 10 Kmph
Speed upstream = 2 Kmph
Let x = speed of rowing
y = speed of the current
x + y = 10
x - y = 2
x = 6 y = 4
Speed of rowing = 6 Kmph
Speed of the current = 4 Kmph
Speed upstream = 2 Kmph
Let x = speed of rowing
y = speed of the current
x + y = 10
x - y = 2
x = 6 y = 4
Speed of rowing = 6 Kmph
Speed of the current = 4 Kmph
midu1:
Thanks a lot my dear friend
Answered by
5
Her speed of rowing in still water = 6 km. per hour ...
the speed of the current = 4 km. per hour ..
let her speed in still water = X km. / hour ..
let the speed of the current = Y km. / hour ...
so her speed of rowing in downstream = (X + Y) km. / hour ..
since .. speed = distance / time
so .. X + Y = 20 / 2
X + Y = 10 ............... (1)
now ... her speed of rowing in upstream = (X - Y) km. / hour ...
again by the rule .... S = D / t
so ..... (X -Y) = 4 / 2
(X - Y) = 2 ......... (2)
by adding equation (1) and (2) ...
X + Y + X - Y = 10 + 2
2X = 12
so ..
X = 12 / 2
X = 6 km. / hour ...
by equation (1) ..
X + Y = 10
6 + Y = 10
Y = 10 - 6 = 4
Y = 4 km. / hour ....
the speed of the current = 4 km. per hour ..
let her speed in still water = X km. / hour ..
let the speed of the current = Y km. / hour ...
so her speed of rowing in downstream = (X + Y) km. / hour ..
since .. speed = distance / time
so .. X + Y = 20 / 2
X + Y = 10 ............... (1)
now ... her speed of rowing in upstream = (X - Y) km. / hour ...
again by the rule .... S = D / t
so ..... (X -Y) = 4 / 2
(X - Y) = 2 ......... (2)
by adding equation (1) and (2) ...
X + Y + X - Y = 10 + 2
2X = 12
so ..
X = 12 / 2
X = 6 km. / hour ...
by equation (1) ..
X + Y = 10
6 + Y = 10
Y = 10 - 6 = 4
Y = 4 km. / hour ....
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