Question

fortan programming sum of series:1+1/2+1/3+1/4+.....+1/51​

Answer 1

Answer:

an=a+(n-1)d

an=1/51

then

1/51=1+(n-1)(-1/2) ( d= 1/2-1)

1/51-1=(n-1)(-1/2)

-50/51= (-1/2)(n-1)

50/51=1/2 (n-1)

50×2/51=n-1

100/51=n-1

n=100/51-1

n=100-51/51

n=49/51

nth term does not fraction

then it is not an ap but it is sequence

hope you understand

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