Question

Forty persons were examined for their Haemoglobin
% in blood (in mg, per 100 ml) and the results were
grouped as below :
Haemoglobin
13.1-14 14.1-15 15.1-16 16.1-17 17.1-18
(mg/100 ml)
No. of persons 8 I 12 T 10 6 4 1
Determine modal value of Haemoglobin % in blood
of a person.​

Answer 1

Step-by-step explanation:

Consider the following table to calculate mode:

 

c

i

 

f

i

13.05-14.05  8

14.05-15.05  12

15.05-16.05  10

16.05-17.05  6

17.05-18.05  4

M

o

d

e

=

l

+

(

f

1

−

f

0

2

f

1

−

f

0

−

f

2

)

×

h

Here,

maximum frequency  

f

1

=

12

⇒

modal class  

=

14.05

−

15.05

lower limit of modal class  

l

=

14.05

   

class size  

h

=

1

preceding frequency of modal class  

f

0

=

8

succeeding frequency of modal class  

f

2

=

10

∴

M

o

d

e

=

14.05

+

(

12

−

8

24

−

8

−

10

)

×

1

∴

M o de

=

14.05 + ( 4 6 ) ×1

∴

M o d e =

14.71

Answer 2

The modal value of the data is 14.7

Step-by-step explanation:

here ,

the maximum class frequency is 12 , and the class corresponding to this frequency is 14.1- 15

so the modal class is 14.1-15

lower limit (l)=14.1

class size (h) = 0.9

frequency (f1) of the modal class = 12

frequency (f0) of class preceeding the modal class = 8

frequency (f2) of class suceeding the modal class = 10

then

$mode = l+ (\frac{(f_1 - f_0)}{2f_1-f_0-f_2})\times h$

$14.1+ (\frac{12-8}{24-8-10} )\times 0.9$

= $14.1+(\frac{4}{6} )\times 0.9$

=14.1 + 0.6

= 14.7

hence ,

the modal value of the data is 14.7

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