Question

Forty slips are placed into a hat, each bearing a number 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10, with each number entered on four slips. Four slips are drawn from the hat at random and without replacement. Let p be the probability that all four slips bear the same 02 Amber Let q be the probability that two of the slips bear a number a and the other two bear a number b not equal to a. What is the value of q/p? ​

Answer 1

Answer:

6

Step-by-step explanation:

P = Desired outcome (Getting all 4 same) ÷ Total outcome

so, P = (4x3x2x1) ÷ (40x39x38x37)

similarly, Q = (4x3x4x3) ÷ (40x39x38x37)

Taking ratio Q/P = 6

(*this is the solution for your question, but if you want to know how 4x3x2x1 and 4x3x4x3 came, then you can look at Probability, Permutations & Combinations topic explanation)