forty solid hemispheres each if diameter 2 cm , are melted to form a solid cone with base diameter 6 cm , find the height of the cone
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solution.
volume of hemisphere= 2/3pi r^3
so, volume= 2/3Pi 1 (radius= 1cm(
so, volume of 40 such hemisphere= 40* 2/3 pi
Now, volume of cone= 1/3 pi r^2*h
Now, volume of cone= volume of 40 hemisphere
=> 1/3* pi (r)^2* 6= 40* 2/3*pi
=> 2 (r)^2= 80/3
=> r ^2= 40/3
=> r^2= 13.3
=> r= √13.3 cm
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Hope it help you my friend.
☺✌✌
volume of hemisphere= 2/3pi r^3
so, volume= 2/3Pi 1 (radius= 1cm(
so, volume of 40 such hemisphere= 40* 2/3 pi
Now, volume of cone= 1/3 pi r^2*h
Now, volume of cone= volume of 40 hemisphere
=> 1/3* pi (r)^2* 6= 40* 2/3*pi
=> 2 (r)^2= 80/3
=> r ^2= 40/3
=> r^2= 13.3
=> r= √13.3 cm
______________
Hope it help you my friend.
☺✌✌
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