Four 12 ohm resistance are connected in parallel .three such combinations are connected in series . What will be the total resistance?
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Answered by
41
Resistance of three resistors in parallel
1/R = 1/12 + 1/12 + 1/12 + 1/12
1/R = 4/12
1/R = 1/3
R = 3 ohms
Three such combinations are connected in series
Total resistance = 3 + 3 + 3 = 9 ohms
So total resistance of the combination is 9 ohms.
1/R = 1/12 + 1/12 + 1/12 + 1/12
1/R = 4/12
1/R = 1/3
R = 3 ohms
Three such combinations are connected in series
Total resistance = 3 + 3 + 3 = 9 ohms
So total resistance of the combination is 9 ohms.
Answered by
9
4 identical resistors 12 ohm each
total resistance = R/n=12/4=3ohm
3 such identical resistors 3 ohm each are connected in series
total resistance =3×3=9 ohm
total resistance = R/n=12/4=3ohm
3 such identical resistors 3 ohm each are connected in series
total resistance =3×3=9 ohm
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