Four 12 ohm resistance are connected in parallel. Three such combinations are connected in series. What will be the total resistance?
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1/rp=1/12+1/12+1/12+1/12
1/rp=4/12
1/rp=1/3
Rp=3 ohms
Therefore 3 such resistors are connected in series = 3+3+3=9 ohms hope this helps you!
1/rp=4/12
1/rp=1/3
Rp=3 ohms
Therefore 3 such resistors are connected in series = 3+3+3=9 ohms hope this helps you!
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