Question

Four 12 ohm resistors are connected in parallel . Three such compination are connected in series . What will be the total resistance .

Answer 1

Resistance (R1) = 12 ohm
No. of resistance in parallel = 4
Total resistance in parallel =
$\frac{1}{12} + \frac{1}{12} + \frac{1}{12} + \frac{1}{12} = 0.33$

No. of resistance in series = 3
Total resistance in series =
0.33 + 0.33 + 0.33 = 0.99

Therefore, total effective resistance is 0.99 ohms.