four angles of a pentagon are 100°,175°,85°and 75°. find the fifth angle. I will mark the best answer as brainliest
Answers
Answered by
40
180 × 3
=540
Fifth angle
=540-(100+175+85+75)
=540-435
=105
=540
Fifth angle
=540-(100+175+85+75)
=540-435
=105
meenakumarigula:
wrong ans.
sorry bhai subtract karne me thodi mistake ho gayi
OK no problem and thanks
your welcome brother.
Answered by
25
The sum of the interior angles of any polygon is
180(n-2)
where, n is the no. of sides of the polygon
Pentagon is a polygon with 5 sides... so,
180(n-2)
=180(5-2)
=180*3
=540 degrees
so the sum of the interior angles of the Pentagon is 540 degrees
Let the unknown angle be x
=100+175+85+75+x=540
435+x=540
x=105 degree
HOPE THE ANSWER IS CORRECT
180(n-2)
where, n is the no. of sides of the polygon
Pentagon is a polygon with 5 sides... so,
180(n-2)
=180(5-2)
=180*3
=540 degrees
so the sum of the interior angles of the Pentagon is 540 degrees
Let the unknown angle be x
=100+175+85+75+x=540
435+x=540
x=105 degree
HOPE THE ANSWER IS CORRECT
wrong
I am extremely sorry
you have to write 445 as 435
I have corrected it.. just check it out
Ya I know... silly mistakes
otherwise I will mark you as brainliest
no problem...
ok
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