Question

four angles of a quadrilateral are in the ratio of 1:2:3:4. find the difference between the greatest and the smallest angle
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Answer 1

Step-by-step explanation:

Sum of all angles of the quadrilateral=360°

4+3+2+1=10

360/10= 36

1st angle= 36°

2nd angle= 72°(36*2)

3rd angle= 108°(36*3)

4th angle= 144°(36*4)

Difference= 144°-36°=108°

Answer is 108°.

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Answer 2

Answer:

Step-by-step explanation:

Now we know that the sum of the interior angles of a quadrilateral measures upto 360 degrees.

With respect to the given question:

1x + 2x + 3x + 4x = 360

10x = 360

x = 360/10 ⇒36

∵ The value of x is found to be 36

Angles of the quadrilateral are

1x = 1(36) = 36

2x = 2(36) = 72

3x = 3(36) = 108

4x = 4(36) = 144

Difference b/w the largest and smallest angle = 144 - 36⇒108 degrees

∴ Difference = 108 degrees

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