Question

Four bad oranges are mixed accidently with 16 good oranges. Find the probability distribution of the number of bad oranges in a draw of two oranges.

Answer 1

Step-by-step explanation:

Total oranges = 16 +4 =20

p(E) = 4/20 = 1/5 ( bad oranges)

Answer 2

Answer:

$\frac{4}{5}$% good $\frac{1}{5}$% bad

Step-by-step explanation:

$16+4=20$

fraction denominator would be $20$

$20-16=4 =|\leq \frac{4}{5} \geq |$

$20-4=16=|\leq \frac{1}{5}\geq |$