Four balls A, B, C and D are projected with the same velocity u making angles of 30°, 45°, 60° and 75° respectively with the horizontal. Which ball will strike the ground at the farthest point ?
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Answer:
R = u^2 sin2theta/g
So R is directly proportional to 2 theta.
Among 30,45,60,75
30 will give sin60 = √3/2
45 will give sin90 = 1(maximum possible value)
60 will give sin120 = √3/2
and 75 sin150 = 1/2
So 45 degree angle is required for max range.
Explanation:
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