four balls are thrown with same initial velocity at an angle of 25 degree 35 degree 45 degree and 69.7 degree with horizontal .which Ball would come back to the ground at earliest and why
Answers
Answered by
14
Hey dear,
◆ Answer-
At θ = 25°
◆ Explaination-
# Given-
θ1 = 25°
θ2 = 35°
θ3 = 45°
θ4 = 69.7°
# Solution-
Time to reach ground in projectile motion is given by -
T = 2usinθ / g
i.e. T ∝ sinθ
At θ = 25°, sinθ = 0.4226
At θ = 35°, sinθ = 0.5736
At θ = 45°, sinθ = 0.7071
At θ = 69.7°, sinθ = 0.9379
As sinθ is least for θ = 25°, T will be lowest.
Therefore, ball thrown with angle 25° will come down earliest.
Hope this helps you...
◆ Answer-
At θ = 25°
◆ Explaination-
# Given-
θ1 = 25°
θ2 = 35°
θ3 = 45°
θ4 = 69.7°
# Solution-
Time to reach ground in projectile motion is given by -
T = 2usinθ / g
i.e. T ∝ sinθ
At θ = 25°, sinθ = 0.4226
At θ = 35°, sinθ = 0.5736
At θ = 45°, sinθ = 0.7071
At θ = 69.7°, sinθ = 0.9379
As sinθ is least for θ = 25°, T will be lowest.
Therefore, ball thrown with angle 25° will come down earliest.
Hope this helps you...
Similar questions
Political Science,
7 months ago
Accountancy,
7 months ago
Chemistry,
7 months ago
Social Sciences,
1 year ago