Question

Four bodies p, q, rands are projected with equal velocities having angles of projection 15,30,45 and 60 with the horizontal respectively. the body having shortest range is

Answer 1

HELLO THERE!

Formula of range is,

$R = \frac{u^{2}sin2\theta}{g}$

where g (acceleration due to gravity), and u (initial velocity) is constant.

So,

When you put θ = 45, the Range that comes is maximum.

When you put θ = 30 or 60, the value of Range comes same (as Range is equal for complementary angles).

So, minimum is the angle (if it is less than 45°), minimum is the range.

Hence, range is minimum when θ = 15°.

So, ball p will have the minimum Range.

Answer 2

Answer:

P

Explanation:

Range of projectile will be minimum for that angle which is farthest from 45°.