Question

Four brothers have Rs45. If the money of the first is increased by Rs2 and the
money of the second is decreased by Rs2, and the money of the third is doubled,
and the money of the fourth is halved, then all of them will have the same
amount of money. How much does each have?

Answer 1

Answer:

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Answer 2

Given total amount = Rs. 45

Let the money got by each one be Rs. X

Since all of them will have the same amount of money.

So,

Money got by First person is increased by Rs. 2

=>Rs. (X+2)

Money got by Second person is decreased by Rs. 2

=> Rs. (X-2)

Money got by Third person is doubled

=> Rs. (2X)

Money got by fourth person is halved

=> Rs. (X/2)

Total money

= (X+2)+(X-2)+(2X)+(X/2)

=X+2+X-2+2X+(X/2)

= 4X+(X/2)

=(8X+X)/2

=9X/2

According to the given problem

Total money = Rs. 45

=>9X/2 = 45

=> 9X = 45×2

=> 9X = 90

=> X = 90/9

=>X = 10

First person got the money = 10+2 = 12

Second person got the money = 10-2 = 8

Third person got the money = 2(10)=20

Fourth person got the money = 10/2 = 5

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