four bulllets abcd are fired with same inital velocity making aangles of 25 40 60 75degree with the horizontal the largest distance will be covered by a b c d
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Answer:
The one fired with an angle 40°
Explanation:
Range of a projectile is give as
- R = u²Sin(2θ)/g
Where
- R = Range of particle
- u = Initial velocity of particle
- θ = Angle of projection with horizontal
- g = Acceleration due to gravity
It's given that all 4 bullets are fired with same initial velocity. So, In the above formula u²/g is constant. Let's denote the constant as k
- R = kSin(2θ)
Range of all the 4 bullets will be then,
- R₁ = kSin(2 × 25°) = kSin(50°) = 0.766k
- R₂ = kSin(2 × 40°) = kSin(80°) = 0.985k
- R₃ = kSin(2 × 60°) = kSin(120°) = 0.866k
- R₄ = kSin(2 × 75°) = kSin(150°) = 0.500k
From above,
- R₄ < R₁ < R₃ < R₂
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