Question

Four buses traverse a distance of 10 km, 20 km
24 km. and 32 km respectively from a bus
stand after a definite interval of time.
What is the minimum distance traversed by
the buses when they meet together​

Answer 1

Answer:

The minimum distance traversed by buses when they meet together is 480 km.

Step-by-step explanation:

LCM of distance travelled by all four buses will give minimum distance traversed by buses when they meet together

$10 = 2 \times 5 \\ 20 = 2 ^{2} \times 5 \\ 24 = 2 {}^{3} \times 3 \\ 32 = {2}^{5}$

LCM ( 10, 20, 24, 32 ) = 2⁵ × 3 × 5

= 480