Question

four candidates ina panchayat election received 526,1132,5432,and2400 vote respectively find the winning votes percentage​

Answer 1

Given:

Four candidates in a panchayat election received 526, 1132, 5432 and 2400 vote respectively.

We have to find, the winning votes percentage​.

Solution:

Total votes received by all candidate = 526 + 1132 + 5432 + 2400

                                                                = 9490

Clearly, winning candidate is received = 5342 votes

∴ The winning votes percentage​ = $\dfrac{Total votes}{Winning candidate votes} \times 100$

= $\dfrac{5432}{9490} \times 100$ %

= 57.23 %

Thus, the required option is "B) 57.23".

Answer 2

Given :  four candidates ina panchayat election received 526, 1132, 5432, and 2400 vote

To Find : Winner vote percentage

23.27 %

57.23 %

67.27 %

54.85 %

Solution:

Votes

526 , 1132 , 5432  and 2400

Total Votes = 526 + 1132 + 5432 + 2400 = 9490

arranging votes in descending order

5432 , 2400 , 1132 , 526

Winner is with Votes = 5432

Vote % = (5432/9490) * 100 = 57.239 %

from the given options 57.23 % is closer

Winner Vote percentage is 57.23  %

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