four candidates ina panchayat election received 526,1132,5432,and2400 vote respectively find the winning votes percentage
Answers
Given:
Four candidates in a panchayat election received 526, 1132, 5432 and 2400 vote respectively.
We have to find, the winning votes percentage.
Solution:
Total votes received by all candidate = 526 + 1132 + 5432 + 2400
= 9490
Clearly, winning candidate is received = 5342 votes
∴ The winning votes percentage =
= %
= 57.23 %
Thus, the required option is "B) 57.23".
Given : four candidates ina panchayat election received 526, 1132, 5432, and 2400 vote
To Find : Winner vote percentage
23.27 %
57.23 %
67.27 %
54.85 %
Solution:
Votes
526 , 1132 , 5432 and 2400
Total Votes = 526 + 1132 + 5432 + 2400 = 9490
arranging votes in descending order
5432 , 2400 , 1132 , 526
Winner is with Votes = 5432
Vote % = (5432/9490) * 100 = 57.239 %
from the given options 57.23 % is closer
Winner Vote percentage is 57.23 %
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