Question

Four capacitors are connected as shown in
circuit. Find its equivalent capacitance.​

Answer 1

Answer:

5 ×10^-6 F

Explanation:

The given circuit can be rearranged into the diagram attached below therefore we can see that the two 2 ×10^-6F capacitor are parallel and the third capacitor 12×10^-6F is in series with them and finally the another 2×10^-6F parallel to that so

Capacitance (c)=1/{(1/(2+2))+(1/12)} +2 (×10^-6F)

=5×10^-6F