Question

four capacitors each of capacity 400pf are charged each to 100v and then they are connected in parallel the energy stored in the system is​

Answer 1

Answer:

8*10^-6

Explanation:

ENERGY OF CAPACITOR FORMULA = (CV^2)/2

4 capacitors are connected in total so...

total energy = 4*(energy of each capacitor)

Capacitance =  400pF = 400 * 10^-12

=> PEnet = 4*(400*10^-12*100*100)/2

=  4 * (4 * 10^-6/2)

PEnet =  8* 10^-6 (final answer)