Question

four cards are drawn from a pack of 52 cards without replacement. what is the probability that they are all different suit​

Answer 1

Step-by-step explanation:

Given:four cards are drawn from a pack of 52 cards without replacement.

To find: what is the probability that they are all different suit

Solution:

A deck has 52 playing cards,having four suits

Each suit has 13 cards

Probability of drawing 4 cads without replacement

$= \frac{13}{52} \times \frac{13}{51} \times \frac{13}{50} \times \frac{13}{49} \\ \\ = \frac{1}{4} \times \frac{13}{51} \times \frac{13}{50} \times \frac{13}{49} \\ \\ P(E) = \frac{2197}{499800}$

Because each time total cards in the deck are 1 less,as cards are drawing one after another without replacement.

Hope it helps you.

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Answer 2

Answer:

Because each time total cards in the deck are 1 less,as cards are drawing one after another without replacement.