Question

four carrom board strikers of radius 3.5cm are so arranged that each striker touches at least two other?

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Answer 1

Answer:

The strikers are arranged such that their diameters and the line joining their centers form a square.

area of empty space = the total area of square that encloses all the 4 circles - the area of the circles.

side of square is diameter of two circles, hence = 2 x 7 => 14 cm

area of all the the circles = 4 x π r² => (88 x 3.5 x 3.5)/7 =>154 cm²

area of empty space = 14² - 154

area of empty space = 196 - 154

area of empty space = 42 cm²

Hope it will help you with the question

Answer 2

Step-by-step explanation:

3.5 *22/7

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