Question

Four cells each of emf 2 volt and each 2ohm internal resistance are used to send a current through wire of 2 ohm resistance. The cells are arranged in series. The current through circuit is_

Answer 1

Answer:

Given data:V=2volt

R=2 ohm

there are 4 resistors...

Solution:Let Req be the net resistance.

since there are 4 resistors in the series combination :-

Req =R1+R2+R3+R4

Req=2+2+2+2

Req =8ohm

Now, By ohm's law,

V=IReq

Therefore, I=V/Req

I=2/8

I=1/4

Therefore, I=0.25ampere

Hence the current flowing through the circuit is 0.25 ampere......

Hope it helps u....... ^.^