Question

Four cells, each of having internal resistance 1 Ω are connected in parallel. The battery resistance will be ?

Answer 1

Answer:Since the battery is connected in parrallel ,

  its resistance is,

 Rp=0.25 ohm

Explanation;

1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4

1/Rp = 1/1 + 1/1 + 1/1 + 1/1

1/Rp = 4/1

Rp = 1/4

Rp = 0.25ohm

Answer 2

Answer:The cells are connected in parallel

Hence,

1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4

1/Rp = 1/1 + 1/1 + 1/1 + 1/1

1/Rp = 4/1

Rp = 1/4

Rp = 0.25

therefore, The battery resistance will be 1/4