Four chairs and 3 tables cost 2100 and 5 chairs and 2 tables cost 1750. Find the cost of one chair and one table ?
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Let the cost of 1 chair be x and cost of 1 table be y
According to the question,
4x + 3y = 2100 ....... (Eqn 1)
5x + 2y = 1750 ........... (Eqn 2)
Multiplying (eqn 1) by 2 and (Eqn 2) by 3,
8x + 6y = 4200 ......... (Eqn 3)
15x + 6y = 5250 ......... (Eqn 4)
(Eqn 4) - (Eqn 3)
7x = 1050
x = 1050 ÷ 7
x = 150
Substituting the value of x in (Eqn 1)
y = 500
Cost of chair = 150
Cost of table = 500
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