Question

Four charges +8q,-3q,+5q and -10q are kept inside a closed surface.What will be outgoinhg flux through the surface

Answer 1

Answer:

Explanation:

through the gauss theorem ..

∑q = (8-3+5-10)q = 0

so out going flux will be zero.

Answer 2

The outgoing flux through the surface will be zero.

Explanation:

Let

$q_1=8q$

$q_2=-3q$

$q_3=5q$

$q_4=-10q$

Total charge inside a closed surface,q=$q_1+q_2+q_3+q_4$

Total charge inside a closed surface,q=8q-3q+5q-10q=0

We know that

Flux,$\phi=\frac{q}{\epsilon_0}$

Where q=Total charge enclosed by the surface

Substitute the values

$\phi=\frac{0}{\epsilon_0}=0$

Hence, the outgoing flux through the surface will be zero.

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