Question

Four charges are placed on the
circumference of a circle of radius R, 90°
apart as shown in the figure. The electric
field strength at the centre of the circle is:
No image​

Answer 1

Answer:

it will be same in all charges

hope it help u

please mark as brainlist

Answer 2

Answer:

The electric field strength at the centre of the circle is zero.

Explanation:

Given that :

• Four charges are placed at circumference at 90⁰ apart

Solution :

• Let the charges be placed at point A, B, C, D at 90⁰ aparts.
• In the figure, charge placed at A and at C are opposite to each other. Similarly, charges placed at B and at D are opposite to each other.
• The electric field at the centre due to charge at A is

$E(1) = k \frac{q}{ {R}^{2} } \: \: towards \: charge \: C$

• The electric field at the centre due to charge at C is

$E(3) = k \frac{q}{ {R}^{2} } \: \: towards \: charge \: A$

• Since, Electric field strength due to charge A and C at centre is equal and opposite. Net electric field is zero.
• Similarly, The electric field at the centre due to charge at B is

$E(2) = k \frac{q}{ {R}^{2} } \: \: towards \: charge \: D$

• The electric field at the centre due to charge at B is

$E(4) = k \frac{q}{ {R}^{2} } \: \: towards \: charge \: B$

• Again, Electric field strength due to charge B and D are equal and opposite, the net electric field is zero.
• Hence, the electric field strength at the centre is zero.