Question

Four charges equal to minus q are placed at four corners of a square

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let a metre the side of the side of the square.The length of a diagonal will be

2

a.The force on the positive charge Q at A due to the positive charge Q at C is F=

4πε

0

1

2a

2

Q

2

and is directed outward,as shown.In order to make net force on Q zero,the resultant of the other two force F

1

and F

2

on Q due to the charges q and q should be equal and opposite to F.Clearly F

1

and F

2

will be directed as shown and for this both q

′

should be negative.

now

F

1

=F

2

=

4πε

0

1

a

2

Qq

since F

1

and F

2

are at right angles, their resultant is

F

12

=

4πε

0

1

a

2

2

Qq

For the equilibrium of Q, we musst have

F=F

12

But Q+

2

μC

∴q=−

2

2

2

μC

=−0.5μC