Question

Four charges of + 6*10-8 C each are
placed at the corners of a square whose
sides a are 3 cm each. Calculate the
resultant force on each charge and shows
in direction an a digram drawn to scale.​

Answer 1

Answer:

solved

Explanation:

let the square be ABCD

we will consider the point A to be at the origin with coordinates ( 0 ,0)

we will calculate the forces acing at A

Force From B  = kq²/d² = 9×10∧9 ×36×10∧-16 ÷  9×10∧-4 = 36×10∧-3 N = F1

Force From D  = kq²/d² = 9×10∧9 ×36×10∧-16 ÷  9×10∧-4 = 36×10∧-3 N = F2

Force From C  = kq²/d² = 9×10∧9 ×36×10∧-16 ÷  18×10∧-4 = 18×10∧-3 N = F3

resultant of F1 and F2 = 36√2×10∧-3 N

acting in the direction of F3 and making 45° with x axis

Total resultant = (18 + 36√2) ×10∧-3 N

the resultant at all points is the same = (18 + 36√2) ×10∧-3 N