Question

Four charges of same magnitude and same sighn are placed at the corners of a square of each side 0.1 m what is electric field intensity at the centre of the square

Answer 1

Answer:

the answer is zero

Explanation:

because the the electric field intensity gets cancelled due to the presence of diagonally opposite charges

Answer 2

FIELD INTENSITY AT CENTRE OF SQUARE IS ZERO.

Let's see why !

• 4 charges (each q and having same sign) is place that each corner of a square having edge length of 0.1 metres.

Now, at the centre, the diagonally opposite charges will produce equal and opposite field intensity vectors which will nullify each other.

The field intensity due to individual charges will be:

$E = \dfrac{kq}{ {\bigg(\dfrac{ \sqrt{ {0.1}^{2} + {0.1}^{2} } }{2} \bigg)}^{2} }$

Now, the field intensity due to each charge will cancel out the field intensity vector of the charge located at the diagonally opposite vertex.

Hence, the net field intensity at centre will be zero