Physics, asked by mallanjali399, 2 months ago

four charges of same magnitude and same sign are placed at the four corhers of a square of each side 10cm what is the electric field intensity at the center of square

Answers

Answered by nirman95
3

Given:

Four charges of same magnitude and same sign are placed at the four corners of a square of each side 10cm.

To find:

Field intensity at centre ?

Calculation:

Field intensity at centre due to one charge:

E=\dfrac{kq}{r^{2}}

\implies E =  \dfrac{kq}{{( \frac{10}{ \sqrt{2} } )}^{2} }

 \implies E =  \dfrac{kq}{50}

Now,

the field intensity of one charge (at one vertex) will cancel the field intensity of the charge at the opposite vertex.

So, field intensity at centre is ZERO.

Attachments:
Answered by 8317045086
0

Answer:

Given:

Four charges of same magnitude and same sign are placed at the four corners of a square of each side 10cm.

To find:

Field intensity at centre ?

Calculation:

Field intensity at centre due to one charge:

E=\dfrac{kq}{r^{2}}E=

r

2

kq

\implies E = \dfrac{kq}{{( \frac{10}{ \sqrt{2} } )}^{2} }⟹E=

(

2

10

)

2

kq

\implies E = \dfrac{kq}{50}⟹E=

50

kq

Now,

the field intensity of one charge (at one vertex) will cancel the field intensity of the charge at the opposite vertex.

So, field intensity at centre is ZERO.

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