four charges of same magnitude and same sign are placed at the four corhers of a square of each side 10cm what is the electric field intensity at the center of square
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Given:
Four charges of same magnitude and same sign are placed at the four corners of a square of each side 10cm.
To find:
Field intensity at centre ?
Calculation:
Field intensity at centre due to one charge:
Now,
the field intensity of one charge (at one vertex) will cancel the field intensity of the charge at the opposite vertex.
So, field intensity at centre is ZERO.
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Answer:
Given:
Four charges of same magnitude and same sign are placed at the four corners of a square of each side 10cm.
To find:
Field intensity at centre ?
Calculation:
Field intensity at centre due to one charge:
E=\dfrac{kq}{r^{2}}E=
r
2
kq
\implies E = \dfrac{kq}{{( \frac{10}{ \sqrt{2} } )}^{2} }⟹E=
(
2
10
)
2
kq
\implies E = \dfrac{kq}{50}⟹E=
50
kq
Now,
the field intensity of one charge (at one vertex) will cancel the field intensity of the charge at the opposite vertex.
So, field intensity at centre is ZERO.
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