Question

Four charges +q,+q,-q and -q are placed respectively at the four corners of a square ABCD whose each side is a calculate the force on charge placed at A

Answer 1

Explanation:

let, the side of the square is a let, +q, +q, -q, -q are arranged as ABCD of the square, then the distance between the two vertices A, D is 2√2

the two forces from the vertices B and C are at right angles , their resultant force is F=9*10^9*q*√2/a^2

the force acts on A due to D is F1=9*10^9* q/8a^2 and hence find thier resultant