Four charges +q,+q, -q and –q are placed respectively at the four corners A,B,C and D of a square of side a. Calculate the force on a charge Q placed at the centre of the square
Answers
Answered by
0
Explanation:
force on Q due to A and C is
F1 = Fa + Fc = 9 x 10⁹ x Qq /(a /√2)² [2]
= 18 x 10⁹ x Qq x 2
= 36 x 10⁹ x Qq
force on Q due to B and D is
F2 = Fb + Fd =36 x10⁹ x Qq
the angle between them is 90⁰
F on Q is
=√( F1² + F2² + 2 x F1 x F2 cos 90⁰)
=√( F1² + F2²)
= √ 2 x ( 36 x10⁹ x Qq)²
= Qq x 36 x 10⁹ √2 N
Similar questions