four charges +q,+q,-q,-q are placed respectively at four corners of a side a. Calculate E at center of square.
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Answered by
1
Answer:
Consider the problem
F
1
by −q and +q on Q charge
F
1
=
(
2
a
)
2
kQq
+
(
2
a
)
2
kQq
=
a
2
4kQq
N
And
F
2
by −q and +q on Q charge
F
2
=
(
2
a
)
2
kQq
+
(
2
a
)
2
kQq
=
a
2
4kQq
N
F
1
=F
2
=
a
2
4kQq
N
Now F Resultant
=
(F
1
)
2
+(F
2
)
2
+2F
1
F
2
cos90
∘
=
2
F
=
2
(
a
2
4kQq
)
=4
2
a
2
kQq
Hence, Option B is the correct answer.
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