Question

Four charges q1=1uC,q2=2uC,q3=3uC and q4=4uC are placed at (0,0,0),(1m,0,0),(0,1m,0) and (0,0,1m) respectively.Let Fi be the net force acting on ith charge of the given system then sigmaFi=
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Answer 1

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Answer 2

Concept Introduction: All charges follow Coulomb's Law of Force of Attraction.

Given:

We have been Given:

$q1 = 1uc \\ q2 = 2uc \\ q3 = 3uc \\ q4 = 4uc$

The points are

$(000)(1m00)(01m0)(001m)$

To Find:

We have to Find: Net force acting on the charge.

Solution:

According to the problem, Net Force is

$f_{i} = \frac{1}{4\pi \times e} ( \frac{qq1}{ { r_{1} }^{2} } + \frac{qq2}{ { r_{2} }^{2} } + \frac{qq3}{ { r_{3} }^{2} } + \frac{qq4}{ { r_{4} }^{2} } + \frac{qq5}{ { r_{5} }^{2} } )$

Therefore putting the values in place,

$f_{i} = 9 \times {10}^{9} \times ( \frac{1 \times 2}{1} + \frac{1 \times 3}{1} + \frac{1 \times 4}{1} + \frac{2 \times 3}{2} + \frac{2 \times 4}{2} =9 \times {10}^{9} \times 16 \\ f_{i} = 144 \times {10}^{9} n$

Final Answer: The Net Charge is

$144 \times {10}^{9} n$

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