Math, asked by vinaya7288, 8 months ago

Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there

Answers

Answered by SidhantVerma77
5

Answer:

There are 65 toys.

Step-by-step explanation:

Let the total no of toys be x

First child have x/10 toys

Second child have x/10 + 12

Third child have x/10 + 1

Fourth child have 2 × x/10 = x/5

By condition,

x/10 + x/10+12 + x/10+1 + x/5 = x

=> 5x/10 + 13 = x => 5x + 130/10 = x

=> 5x + 130 = 10x => 10x - 5x = 130

=> 5x = 130 => x = 130/5 = 65 {answer}

PLEASE SELECT MY ANSWER AS THE BRAINLIEST ANSWER.

Answered by kaleabmj
0

Answer:

Toys

Logic Puzzles

Permutations and Combinations

Mathematics Word Problems

Child Development

+5

4 children have small toys. First child has 1/10 of the toys, second child has 12 more toys than the first, third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there?

Answer

Toys

Logic Puzzles

Permutations and Combinations

Mathematics Word Problems

Child Development

+5

4 children have small toys. First child has 1/10 of the toys, second child has 12 more toys than the first, third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there?

Answer

Follow

·

2

Request

Ad by Forge of Empires

Through the ages!

Develop a civilization from the stone age to the future in this award-winning game.

Learn More

17 Answers

Profile photo for Wesley Long

Wesley Long, worked at Bill Young Productions

Answered March 6, 2019

30.

T = Number of toys.

A, B, C, & D = Children 1 - 4

Givens:

A = T/10

B = A+12

C = A + 1

D = 2C

Substitution in terms of T:

A = T/10

B = T/10 + 12

C = T/10 + 1

D = 2 (T/10 + 1)

Known: The 4 children have all the toys

T = A + B + C + D

Substitution in terms of T:

T = T/10 + T/10 + 12 + T/10 + 1 + 2(T/10 + 1)

Reduce parenthetical(s)

T = T/10 + T/10 + 12 + T/10 + 1 + 2T/10 + 2

Multiply both sides by 10 to remove divisors.

10T = T + T + 120 + T +10 + 2T +20

Simplify expression on right-hand side

10T = 5T + 150

Balance equation, placing all of T on one side, and all constants on the other

5T = 150

Divide both sides of equation by 5 to resolve T

T = 30

Follow

·

2

Request

Ad by Forge of Empires

Through the ages!

Develop a civilization from the stone age to the future in this award-winning game.

Learn More

17 Answers

Profile photo for Wesley Long

Wesley Long, worked at Bill Young Productions

Answered March 6, 2019

Similar questions