Question

Four children went on an egg hunt and found a total of 45 eggs. Each child had a different number of eggs, but if a had 2 more, b had 2 less c had twice as many and D had half as many they would all have the same number can you tell how many eggs each child found? Using arithmetic formula

Answer 1

Step-by-step explanation:

Let x be the same number of eggs

A=x+2

B=x-2

C=2x

D=1/2x

A+B+C+D=45

x+2+x-2+2x+1/2x=45

4x+1/2x=45

8x+x=45×2

9x=90

x=10

A=x+2=10+2=12

B=x-2=10-2=8

C=2x=2×10=20

D=1/2x=1/2×10=5

Answer 2

Answer:

x = 10

Step-by-step explanation:

No. of eggs Child A has = x+2

No. of eggs Child B has = x-2

No. of eggs Child C has = 2x

No. of eggs Child D has = 1/2×x = x/2

(x + 2) + (x - 2) + 2x + x/2 = 45

2x + 2x + x/2 = 45

4x + x/2 = 45

8x/2 + x/2 = 45

9x/2 = 45

9x = 45 × 2

9x = 90

x = 90/9

x = 10

No of eggs Child A has = x + 2 = 10 + 2 = 12

No of eggs Child B has = x - 2 = 10 - 2 = 8

No of eggs Child C has = 2x = 2 × 10 = 20

No of eggs Child D has = 1/2 × x = 1/2 × 10 = 5

12 + 8 + 20 + 5 = 45

45 = 45

Hence, the answer is correct.

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