Question

four coins are tossed find the probability of getting at least 2 tails ​

Answer 1

t,t,h,h , t,t,t,h. , hhht

Answer 2

let 'S' be the sample space

s=(TTTT, TTTH, TTHT, THTT, HTTT, HHHH, HHHT, HHTH, HTHH, THHH)

n(s)=10

EVENT :A--

getting at least 2 tail

A=(TTTT, TTTH, TTHT, THTT, HTTT)

hence,

n(A)=5

P(A)=n(A)/n(s)

= 5/10

= 1/2.

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