four coins are tossed simultaneously 100 times with the following frequency of different outcomes their outcomes are 4 head 3 head 2head 1head no head and their frequency are18,26,32,16,8
compute the probability of
two head turning up
no head turning up
PLZZ it's urgent
step by step
Answers
Given : four coins are tossed simultaneously 100 times
Frequency of different outcomes
outcomes Frequency
4 heads 18
3 heads 26
2 heads 32
1 heads 16
No heads 8
To Find : probability of
two head turning up
no head turning up
Solution:
n(S) = 100
A =two head turning up
n(A) = 32
P(A) = n(A)/n(S)
=> P(A) = 32/100
=> P(A) = 0.32
=> Probability of two head turning up = 0.32
B =no head turning up
n(B) = 8
P(B) = n(B)/n(S)
=> P(B) = 8/100
=> P(B) = 0.08
=> Probability of no head turning up = 0.08
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Answer:
i) 32/100= 0.32
ii) 8/100= 0.08