Question

Four coins are tossed simultaneously with the following frequency of different outcomes.
Outcome
4 heads
3 heads
2 heads
1 head
No heads
18
26
Frequency
32
16
8
Compute the probability of:
(i) 2 heads turning
(ii) no heads turning
(iii) 4 heads turning up
(iv) 5 heads turning up

Answer 1

Answer:

Answer 2) : 3 heads coming up

Probability = 12/100

= 3/25

Answer 3) : At least 1 head coming up

Probability = (36/100 + 38/100 + 12/100)

= 86/100

= 43/50

Answer 4) : Getting more heads than tails

Number of times 2 heads (2 heads and 1 tail) appears = 36

Number of times 3 heads (3 heads and 0 tail) appears = 12

Number of favorable outcomes = 36 + 12 = 48

Probability (Getting more heads than tails)

= Number of favorable outcomes/Total number of possible outcomes

= 48/100

= 12/25

Answer 5) : Getting more tails than heads

Number of times 2 tails (2 tails and 1 head) appears = 38

Number of times 3 tails (3 tails and 0 head) appears = 14

Number of favorable outcomes = 38 + 14 =52

Probability (Getting more tails than heads) = 52/100

= 13/25

Step-by-step explanation:

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