Four concurrent forces10 kN, 20kN, 30kN and 40kN acting at an angle of 20°, 63°, 95°,150° from positive x axis. Determine their resultant in kN.
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Given : Four concurrent forces10 kN, 20kN, 30kN and 40kN acting at an angle of 20°, 63°, 95°,150° from positive x axis.
To Find : their resultant in kN
Solution:
Horizontal forces
= 10 cos20° + 20 cos63°+ 30cos95° + 40cos150°
= 9.397 + 9.08 - 2.615 - 34.641
= -18.779 kN
Vertical forces
= 10 sin20° + 20 sin63°+ 30sin95° + 40sin150°
= 3.42 + 17.82 + 29.886 +20
= 71.126 kN
resultant in kN. = √(-18.779)² +(71.126)²
= 73.563 kN
their resultant in kN. = 73.563
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