Question

Four conductors of resistance 16 Ohm interconnected to form a square the equivalent resistance across two adjacent corners is

Answer 1

This is your answer given below you can understand it

Answer 2

Answer:

Equivalent resistance is 12 Ω.

Explanation:

It is given that, Four conductors of resistance 16 Ohm interconnected to form a square.

Let ABCD is a square having resistances 16 ohm. So, the resistances in arm AD, DC and CB are in series.

So, their equivalent resistance is given by :

$R_s=3\times 16\ \Omega=48\ \Omega$

Now $R_s$ and resistance in arm AB are in parallel.

$\dfrac{1}{R_{eq}}=\dfrac{1}{48}+\dfrac{1}{16}$

$R_{eq}=12\ \Omega$

The equivalent resistance across two adjacent corners is 12 Ω. Hence, this is the required solution.