four congruent isosceles right triangle are cut from the four corner of a square with side of 20 unit the length of one leg of the triangle is equal to 4 unit the area of the remaining octagon is
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The area of remaining octagon is 168 units.
Let the square be = A
Let the triangle be = B
Finding the area of square A
Area of square = (side)²
A = 20 × 20
= 400 square units
Finding the area of small triangle = B
Area of Triangle = 1/2 × l × b
B = (1/2) × 4 × 4
= 8 square units
Area of the octagon = Area of triangles - Area of square
= A - 4B
= 200 - 4 × 8
= 168 square units
Therefore, the area of remaining octagon is 168.
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